One particular neutron star has a mass equal to 3.00 times the mass of the sun. You may consider this neutron star to be a sphere with a uniform density of 3.30×10^{17} kg/m3 !! ......compare that to the density of lead for example, at 1×10^{4} kg/m3 . (A neutron star is created when a massive star runs out of hydrogen fuel and collapses at the end of its life. The neutron star is a very dense and spins rapidly). If needed, the mass of the sun is 1.99×10^{30} kg
Part A
What's the rotational inertia of the neutron star?
Express your answer with the appropriate units.


INS = 
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Part B
The neutron star's spin rate slowly decreases as a result of torque associated with magnetic forces. If the spindown rate is 4.50 ×10?5 rad/s2, what's the magnitude of the magnetic torque?
Express your answer with the appropriate units.


? = 
A)
Mass of the star, M = 3*Ms
= 3*1.99*10^30
= 5.97*10^30 kg
let R is the radius of the star.
we know,
density = mass/volume
volume = mass/density
(4/3)*pi*R^3 = 5.97*10^30/(3.30*10^17)
R = 16285 m
the rotational inertia of the neutron star,
I = (2/5)*M*R^2
= (2/5)*5.97*10^30*16285^2
= 6.33*10^38 kg.m^2 <<<<<<<<<<Answer
B) we know,
Torque = I*alfa
= 6.33*10^38*4.5*10^5
= 2.85*10^34 N.m <<<<<<<<<<Answer
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