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The object blocked the photogate for an average time of t=(0.01693±0.00005)s The length of the object...

The object blocked the photogate for an average time of t=(0.01693±0.00005)s

The length of the object is d=(2.540±0.001)cm

Find the absolute error of your calculated velocty

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Answer #1

As per the given data:

Average time = 0.01693 +/- 0.00005 sec

therefore Tmax = 0.01693+0.00005 = 0.01698 s

and Tmin = 0.01693-0.00005 = 0.01688 s

Similarly Dmax = 2.54 + 0.001 = 2.541cm

Dmin = 2.54 - 0.001 = 2.539 cm

Now we know that velocity (V) = Distance (D) / time (T)

The photogate determines the speed by calculating the time for which the beam is blocked by object.

Now the block time will be maximum when the distance travelled is maximum & vice versa

Hence V1 = Dmax / Tmax = 2.541 / 0.01698 = 149.6466 cm/sec

and V2 = Dmin / Tmin = 2.539 / 0.01688 = 150.4147 cm/sec

Mean velocity V = (V1+V2) / 2 = 150.0306

Error = Vmax - V OR V - Vmin = 0.384

Hence Velocity = 150.0306 +/- 0.384

Thus the absolute error = 0.384.

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