You have a 9-V battery, a set of 10 50-Ω resistors, and a long (2-m ) connecting wire. Take the thickness of the wire to be 0.6 mm and the radius of solenoid to be 1 cm .
Estimate the maximum magnitude of the B→ field that you can produce with this equipment.
when, 10 and 50 ohms are connected in parallel, net resistance will be less and more current
Rnet = 10*50/(10+50)
= 8.33 ohms
flows through the solenoid and we get maximum magnetic field.
no of turns, N = length of the wire/(2*pi*r)
= 2/(2*pi*0.01)
= 32
length of the solenoid, L = N*t
= 32*0.6 mm
= 19.2 mm
= 0.0192 m
current through solenoid, I = V/Rnet
= 9/8.33
= 1.08 A
so, maximum magnetic field through solenoid, Bmax = mue*N*I/L
= 4*pi*10^-7*32*1.08/0.0192
= 2.26*10^-3 T <<<<<<<<<---------Answer
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