Question

Consider a spherical, homogeneous planet with a radius of rp=3985 km and a mass of mp=8.97×1024 kg. A spherical object with a radius of r0=9.21 m and mass m0=868 kg approaches the planet.

Part 1) When the object is 5.33×109 km away from the planet, what is the magnitude of the force the planet exerts on the object? F= N

Part 2) When the object is 8.10 m above the surface of the planet, what is the magnitude of the gravitational force of the planet on the object? F= N

Part 3) What is the acceleration due to gravity on objects close to the surface of this planet? g= m s?2

Answer #1

**Given **

**mass of planet is mp = 8.97*10^24 kg**

**radius of planet is rp = 3985000 m**

**mass of object mo = 868 kg, radius is ro = 9.21
m**

**Part 1**

**the distance from object to the planet is r = 5.33*10^12
m**

**From F = G*m1*m2/r^2**

**F =
6.674*10^-11*8.97*10^24*868/(5.33*10^12)^2N**

**F = 1.829127387544*10^-8 N**

**Part2**

**if r = 8.10+3985000 +9.21 m**

**F = 6.674*10^-11*8.97*10^24*868/(8.10+3985000 +9.21)^2
N**

**F = 32721.8573 N**

**Part3**

**F = mg**

**g = F/m**

**g = 32721.8573/868 m/s2**

**g = 37.7 m/s2**

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