Question

A primitive diving bell consists of a cylindrical tank with one end open and one end closed. The tank is lowered into a freshwater lake, open end downward. Water rises into the tank, compressing the trapped air, whose temperature remains constant during the descent. The tank is brought to a halt when the distance between the surface of the water in the tank and the surface of the lake is 35.0 m. Atmospheric pressure at the surface of the lake is 1.01 105 Pa. Find the fraction of the tank's volume that is filled with air.

Answer #1

The distance between the surface of the water in the tank andthe
surface of the lake is (h) =38.0m.

The Atmospheric pressure at the surface of the lake
is(P_{surface})=1.01*10^{5}Pa

The density of the warwe is(?)=1000kg/m3

The acceleration due to gravity is(g)=9.8m/s2

Now finding the absolute pressure at a depth h is

p_{h} =Psurface +?gh

=1.01*10^{5}Pa+(1.00*10^{3}kg/m3)(9.8m/s2)(35.0m)

=4.44*10^{5}pa

From the Boyle' law we can write as

V_{h}/V_{tank} =Psurface/P_{h}

=1.01*10^{5} Pa/(4.44*10^{5}pa)

=0.22

A diving bell is a 3.4 m -tall cylinder closed at the upper end
but open at the lower end. The temperature of the air in the bell
is 30 ∘C. The bell is lowered into the ocean until its lower end is
100 m deep. The temperature at that depth is 10∘C.
a)
How high does the water rise in the bell after enough time has
passed for the air to reach thermal equilibrium?
Express your answer to two...

A diving bell is a 4.4 m -tall cylinder closed at the upper end
but open at the lower end. The temperature of the air in the bell
is 30∘C. The bell is lowered into the ocean until its lower end is
100 m deep. The temperature at that depth is 10∘C.
Part A)
How high does the water rise in the bell after enough time has
passed for the air to reach thermal equilibrium?
Express your answer to two...

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