Question

A circuit consists of a power supply and two resistors R1 and R2 connected in parallel. An ammeter is placed to measure the current through resistor R1.

The ammeter reads I1 = 9.6 mA, and the values of the resistors are R1 = 6.0 kOhm and R2 = 820 Ohm.

What is the value of voltage across R2?

Answer #1

R1 = 6 X 10^3 Ohm

i1 = 9.6 x 10^-3 amp

**in parallel combination potential across each resistor
is same**

**
V1 = V2**

**
i1 R1 = V2**

**
V2 = 9.6 x 10^-3* 6 X 10^3**

**
V2 = 57.6 Volts**

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