A circuit consists of a power supply and two resistors R1 and R2 connected in parallel. An ammeter is placed to measure the current through resistor R1.
The ammeter reads I1 = 9.6 mA, and the values of the resistors are R1 = 6.0 kOhm and R2 = 820 Ohm.
What is the value of voltage across R2?
R1 = 6 X 10^3 Ohm
i1 = 9.6 x 10^-3 amp
in parallel combination potential across each resistor is same
V1 = V2
i1 R1 = V2
V2 = 9.6 x 10^-3* 6 X 10^3
V2 = 57.6 Volts
Get Answers For Free
Most questions answered within 1 hours.