Question

A high altitude jet airplane has a velocity relative to the air of 320 m/s due west. At a certain moment, the pilot notices a mountain peak directly west of

the plane at a horizontal distance of 4.20 km. 10 s later, the peak is observed to be a horizontal distance 4.18 km away in a direction 17?north of west.

(a) Set up a coordinate system and given the components of the displacement

vectors between the airplane and the mountain for both the initial and the final time.

(b) Use the information above to find the wind velocity.

Answer #1

This happened in 10 s so, assuming constant velocity, the south
component of velocity of plane is 122 m/s relative to ground.

Since the plane is moving due west relative to air, then the only
way for it to move south was for the air to move south at that
speed.

Now,

Without the wind it would be 320 m/s, so that means the wind is
blowing it back (east) at the speed of 320 - 20 = 300 m/s

Wind velocity = 300 m/s east + 122 m/s south.

(or)

324m/s 22.2° south of east.

Write Algebraically unit vector i point west and j south.

Solve this, You will get:

An airplane is flying at an altitude of 10 km at 120 m/s. Its
jet engines, which for now can be approximated as a converging
duct, have an inlet diameter of 1.5m and an exit diameter of 0.3m.
The exit of the engine has a temperature altitude of 11 km, and
pressure altitude of 10.5 km.
a. Is the flow incompressible or compressible? How do you
know?
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certain altitude, where the ambient conditions are 32 kPa and
-32°C. The pressure ratio across the compressor is 12, and the
temperature at the turbine inlet is 1400K. Air enters the
compressor at a rate of 40 kg/s, and the and the jet fuel has a
heating value of 42700 kJ/kg. Assuming ideal operations for all
components and constant specific heats for air at room temperature,
(Cp=1.005...

An airplane with a speed of 90.8 m/s is climbing upward at an
angle of 54.1 ° with respect to the horizontal. When the plane's
altitude is 836 m, the pilot releases a package.
(a)Calculate the distance along the ground,
measured from a point directly beneath the point of release, to
where the package hits the earth. (b) Relative to
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angle of 32.0 ° with respect to the horizontal. When the plane's
altitude is 980 m, the pilot releases a package.
(a) Calculate the distance along the ground,
measured from a point directly beneath the point of release, to
where the package hits the earth. (b) Relative to
the ground, determine the angle of the velocity vector of the
package just before impact.

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angle of 36.1 with respect to the horizontal. When the plane's
altitude is 939m, the pilot releases a package. (A) calculate the
distance along the ground, measured from a point directly beneath
the point of release to where the package hits the earth. (B)
relative to the ground, determine the angle of the velocity vector
of the package just before impacy?

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angle of 62.3 ° with respect to the horizontal. When the plane's
altitude is 719 m, the pilot releases a package. (a) Calculate the
distance along the ground, measured from a point directly beneath
the point of release, to where the package hits the earth. (b)
Relative to the ground, determine the angle of the velocity vector
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angle of 43.5 ° with respect to the horizontal. When the plane's
altitude is 860 m, the pilot releases a package. (a) Calculate the
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the point of release, to where the package hits the earth. (b)
Relative to the ground, determine the angle of the velocity vector
of the package just before impact.

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angle of 45.2 ° with respect to the horizontal. When the plane's
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the point of release, to where the package hits the earth. (b)
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X-velocity V0x= 360 m/s at
an altitude (height above the ground)=H=Dy= 3645
m. A bag of mass M=40 Kg falls off from
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