The intensity of electromagnetic wave B is four times that of wave A. How does the magnitude of the electric field amplitude of wave A compare to that of wave B?
The electric field amplitude of wave A is one-fourth that of wave B
The electric field amplitude of wave A is three times that of wave B
The electric field amplitude of wave A is two times that of wave.
The electric field amplitude of wave A is four times that of wave B
The electric field amplitude of wave A is one half that of wave B
Intensity = (Electric field Amplitude)2
intensity of B wave
and intensity of A wave
According to question
so
It means The electric field amplitude of wave A is one half that of wave B.
# Last option is right.
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