Question

An ideal monatomic gas expands isothermally from 0.600 m3 to 1.25 m3 at a constant temperature of 730 K. If the initial pressure is 1.02 ? 105 Pa find the following.

(a) the work done on the gas

J

(b) the thermal energy transfer Q

J

(c) the change in the internal energy

J

Answer 1

------------------------ Solution of Part a ---------------------------------------

Work done in an Isothermal process is given by

and we have initial condition as

using this value we can calculate workdone in the process as

So work done on the Gas is 4.5*10^4 J

------------------------ Solution of Part b ---------------------------------------

as per law of energy we have.

Since in isothermal process there is no change in internal energy so

and

So

SO thermal energy transfer is equal to 4.5 *10^4 J

------------------------ Solution of Part c ---------------------------------------

Change in internal enrgy of the system is Zero