Question

An ideal monatomic gas expands isothermally from 0.600 m3 to 1.25 m3 at a constant temperature of 730 K. If the initial pressure is 1.02 ? 105 Pa find the following.

(a) the work done on the gas

J

(b) the thermal energy transfer Q

J

(c) the change in the internal energy

J

Answer #1

------------------------ Solution of Part a ---------------------------------------

Work done in an Isothermal process is given by

and we have initial condition as

using this value we can calculate workdone in the process as

**So work done on the Gas is 4.5*10^4 J**

**------------------------ Solution of Part b
---------------------------------------**

**as per law of energy we have.**

**Since in isothermal process there is no change in
internal energy so**

**and**

So

**SO thermal energy transfer is equal to 4.5 *10^4
J**

**------------------------ Solution of Part c
---------------------------------------**

**Change in internal enrgy of the system is
Zero**

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