Question

Your starship, the Aimless Wanderer, lands on the mysterious planet Mongo. As chief scientist-engineer, you make the following measurements: a 2.50-kg stone thrown upward from the ground at 15.0m/s returns to the ground in 8.00s ; the circumference of Mongo at the equator is 1.00 apply the kinematic equatioin for time of flight t = 2u/g so gravity on mongo is g = 2u/t g = 2* 15/(8) g = 3.75 m/s^2 I need a full explanation of how did he get the g (g=2u/t)

Answer 1

Kinematic equation

When an object is thrown up with an initial vertical velocity , it reaches a maximum height , and again reaches ground in time .

The vertical height travelled by object in going up and coming down is

Acceleration of the object is ( negative sign indicates that the gravity is downwards )

Using all these terms in the kinematic equation