Question

A uniformly charged disk of radius 35.0 cm carries a charge density of 7.30 ✕ 10-3 C/m2. Calculate the electric field on the axis of the disk at the following distances from the center of the disk.

(a) 5.00 cm

(b) 10.0 cm

(c) 50.0 cm

(d) 200 cm

Answer 1

According to the given problem,

Given the charge density, use
Ez = kσ2π * (1 - z / √(z² + R²))
Ez = 8.99*10⁹N·m²/C²*7.30*10^-3C/m² * 2π * (1 - z / √(z² + R²))
Ez = 4.1235*10⁸N/C * (1 - [z / √(z² + 35²)]) → for z in ► centimeters ◄

(a) when z = 5.00 cm, Ez = 3.54*10⁸ N/C

(b) when z = 10.0 cm, Ez = 2.991*10⁸ N/C

(c) when z = 50.0 cm, Ez = 7.454*10⁷ N/C

(d) when z = 200 cm, Ez = 6.173*10⁶ N/C.

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