A 1.9-A current is flowing in a 24-H inductor. A switch opens, interrupting the current in 1.0 ms.
Find the induced emf in the inductor.
Inductance L = 24 H
Change in current di = 1.9 A
Tine interval dt = 1 ms = 1 * 10 -3 s
So, Induced emf E = -L di / dt
= -24 *1.9 / 10 -3 V
= 45.6 kV
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