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A small bullet of mass m=0.27g and speed v=13m/s embeds in a block of mass M=0.98kg...

A small bullet of mass m=0.27g and speed v=13m/s embeds in a block of mass M=0.98kg suspended by a massless string of length L, after a collision as shown in the figure. If the bullet will appear on the other side of the block M with a speed v'=3.6m/s, instead of being embedded in it, find the maximum height the block M can reach. (Take g=9.81 m/s2). Express your answer using two decimal places.

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Answer #1

The momentum will be conserved in this collision

m -> Mass of bullet ; v -> Initial velocity of bullet ; v' -> Final velocity of bullet

M -> Mass of block    ; V -> Final velocity of block

Final velocity of the block :

This Kinetic energy due to this changes to potential energy :

Maximum Height :

Substituting :

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