Question

The sound intensity of a conversation at a distance of 6.0 m is 1.7 x 10^-7 W / m^2 . Determine the intensity at a distance of 5.0 m. Assume that the sound spreads evenly in all directions. (10 points)

Answer 1

sound intensity is sound per uinit area perpendicular to the path of the sound wave   sound intensity = I W/m2 (watt per square meter)

I = P/A

P = sound power

A = area

for distance 6m A= 6m and I = 1.7*10-7 W/m2

P = A*I = 6*1.7*10-7 W = 10.2*10-7 W

so, sound power = P = 10.2*10-7 W

Now for distance 5m

A=5m and P =10.2*10-7 W

I = P/A = 10.2*10-7/5  W/m2 = 2.04 *10-7 W/m2

Hence , the intensity at a distance of 5.0 m is 2.04*10-7 W/m2

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