Question

In an RLC series Circuit, the source has an rms potential difference V=60 V and a...

In an RLC series Circuit, the source has an rms potential difference V=60 V and a frequency of 250/pi Hz, while R=50 Ohm and C= 10 uF. If the peak potential difference across R is 25 V, find L. (There are two possible values)

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Homework Answers

Answer #1

Capacitive reactance

XC=1/2pifC =1/2pi*(250/pi)*(10*10-6) =200 ohms

Current flowing in the circuit

Ip=VR/R =25/60 =0.4167 A

rms current

Irms=0.4167/sqrt(2) =0.2946 A

Impedance

Z=V/I =60/0.2946=203.646753 ohms

Impedance

Z=sqrt[R2+(XL-XC)2]

203.646753 =sqrt[502+(XL-200)2]

41472 =2500 + (XL-200)2

XL-200 =(+ or -) 197.4

Case 1 :

XL-200 =-197.4

XL=2.6 ohms

L=XL/2pif =2.6/2pi*(250/pi)

L=5.173*10-3 H

Case 2:

XL-200 =197.4

XL=397.4 ohms

=>L=397.4/2pi*(250/pi)

L=0.795 H

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