Question

A scuba diver takes a tank of air on a deep dive. The tank's volume is 10 L and it is completely filled with air at an absolute pressure of 237 atm at the start of the dive. The air temperature at the surface is 85 ?F and the diver ends up in deep water at 60 ?F.

Assuming thermal equilibrium and neglecting air loss, determine the absolute internal pressure of the air when it is cold.

Answer #1

The pressure P_{1} = 237 atm

The temperature T_{1} = 85 F or 29.44 deg = 302.44 K

and the temperature T_{2} = 60 F or 15.56 deg = 288.56
K

From Ideal gas equation

P_{1}
V_{1} / T_{1} = P_{2}
V_{2}/T_{2}

then

P_{1}/T_{1} = P_{2} /T_{2} (when
it is in equilibrium)

Therefore the pressure

P_{2} =
(T_{2}/T_{1}) P_{1}

= (288.56/302.44) (237)

= 226.12 atm

**the absolute
internal pressure of the air when it is cold is 226.12
atm**

2. An aluminum scuba tank, which has an internal volume of 11.1
L, is filled with air to a pressure of 3000 psi when at room
temperature (i.e. 20.0 OC). A diver takes the tank into seawater,
where the water temperature is 46 degrees Fahrenheit (i.e. 8.00OC).
To what pressure does the air in the tank drop? (The thermal
coefficient of expansion for aluminum is 24.0x10-6 OC -1 .)
Answer: 2880 psi
Please show steps and pictures!

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where the water temperature is 46 degrees Fahrenheit (i.e. 8.00OC).
To what pressure does the air in the tank drop? (The thermal
coefficient of expansion for aluminum is 24.0x10-6 OC -1 .)
Answer: 2880 psi
Don't need #2, just #3 please.
3. For...

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