Question

A laboratory capacitor consists of two parallel conducting plates, each with area of 2*10^-2 m^2 separates...

A laboratory capacitor consists of two parallel conducting plates, each with area of 2*10^-2 m^2 separates by a 4*10^-3 m air gap.

A) compute the capacitance of the capacitor

B) if the capacitor is connected across a 500 V source, find the value of the electrical field between the plates
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Answer #1

Area=

seperation=

A.) Capacitance = where = Relative permiability of the free sky.

F

B.)

Hence electric field intencity in between the plates is

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