Question

A computer is reading data from a rotating CD-ROM. At a point that is 0.0104 m from the center of the disk, the centripetal acceleration is 204 m/s². What is the centripetal acceleration at a point that is 0.0727 m from the center of the disc?

Answer 1

Angular speed of the CD-ROM =

Distance of the first point from the center of the disk = R₁ = 0.0104 m

Centripetal acceleration of the first point = a₁ = 204 m/s²

a₁ = ²R₁

204 = ²(0.0104)

= 140.05 rad/s

Distance of the second point from the center of the disk = R₂ = 0.0727 m

Centripetal acceleration of the second point = a₂

a₂ = ²R₂

a₂ = (140.05)²(0.0727)

a₂ = 1426 m/s²

Centripetal acceleration of a point 0.0727 m from the center of the disc = 1426 m/s²