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A computer is reading data from a rotating CD-ROM. At a point that is 0.0104 m...

A computer is reading data from a rotating CD-ROM. At a point that is 0.0104 m from the center of the disk, the centripetal acceleration is 204 m/s2. What is the centripetal acceleration at a point that is 0.0727 m from the center of the disc?

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Answer #1

Angular speed of the CD-ROM =

Distance of the first point from the center of the disk = R1 = 0.0104 m

Centripetal acceleration of the first point = a1 = 204 m/s2

a1 = 2R1

204 = 2(0.0104)

= 140.05 rad/s

Distance of the second point from the center of the disk = R2 = 0.0727 m

Centripetal acceleration of the second point = a2

a2 = 2R2

a2 = (140.05)2(0.0727)

a2 = 1426 m/s2

Centripetal acceleration of a point 0.0727 m from the center of the disc = 1426 m/s2

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