Question

A.)An electron ejected at a high rate of speed from a solar flare impacts the earth’s magnetic field and spirals down toward the North Geographic Pole. What would be the magnitude of the local magnetic field required to cause the electron to emit electromagnetic radiation at a frequency of 101.5Mhz
B.)In the previous problem, how fast would this electron have to be moving in order for it to move in a circular orbit of radius 1 mm?

Answer 1

Part A)-

F = QvB = mv²/r

QB = mv/r (Here v/r = )

QB = m

B = m/Q

B= (9.1*10^-31)(2*101.5*10⁶) / (1.6*10^-19)

B = 3626.37 *10^-6 T

Part B)-

r = 10^-3 m

V =r

V = (2*101.5*10⁶)*10^-3

V = 637.74 * 10³ m/s

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