The moon Io orbits Jupitor at a distance of 421800 Km with period 1.769 days. If the Ganymede orbits Jupiter at a distance of 1070400 Km, what is its period?
We know from keplers third law that
where T is the time period and 'r' is the radius of orbit
From the above equatio it is clearly visible that T2 ? r3 that is T ? r3/2
So T = 1.769*(1070400/421800)3/2 = 7.15 earth days
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