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A 7.00 kg block sits on the floor at rest. Block is being pulled across a...

A 7.00 kg block sits on the floor at rest. Block is being pulled across a frictionless floor with a force F=14 N at an angle of 35 degrees. What is the magnitude of block’s acceleration?
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Answer #1

mass of the block m = 7 kg

force exerted by cord F = 14 N

angle ? = 350 (above the horizontal)

a)

apply Newton's second law of motion ,

          F cos? = ma

     acceleration a = F cos? /m

                            = (14 N)(cos35) / (7 kg)

                            = 1.64 m/s2

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