Suppose that all the energy from a 75-watt light bulb came in the form of photons with wavelength 600 nm (This is not quite realistic.)
A. Calculate the energy of a single photon with wavelength 600 nm.
B. How many 600-nm photons must be emitted each second to account for all the light from this 75-watt light bulb?
Power P = 75w
wavelength = 600nm = 600 x 10-9 m
A. Energy of each Photon E = h = hc /
=( 6.626 x 10-34 x 3 x 108 ) / 600 x 10-9
= 3.31 x 10-19 J
B) 75 watt means 75joules of energy must be emitted in one second
No. of photons are emitted in one second = Total energy / Energy of each photon
= 75 / 3.31 x 10-19
= 22.66 x1019
= 2.3 x 1020 photons
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