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± Fringes from Different Interfering Wavelengths
Coherent light with wavelength 592 nm passes through two very narrow slits, and the interference pattern is observed on a screen a distance of 3.00 m from the slits. The first-order bright fringe is a distance of 4.84 mm from the center of the central bright fringe.
Part A
For what wavelength of light will the first-order dark fringe (the first dark fringe next to a central maximum) be observed at this same point on the screen?
Express your answer in micrometers (not in nanometers).
ANSWER:
_______ | ?m |
Young's double-slit experiment
path difference = d*sintheta
d*sintheta = m*lambda
for small angles
sintheta = tantheta = y/R
for bright fringe
------------------
path difference = m*lambda_1
d*y/R = m*lambda_1
y = m*lambda_1*R/d
d = slit width
m = order of bright fringe
R = distance between screen and slit
y = position of bright fringe on screen
for first bright
m = 1
y1bright = lambda_1/*R/d
at the same y if dark fringe forms for wavelength lambda 2
for dark fringe
----------------
path difference = (m+1/2)*lambda_2
d*y/R = (m+1/2)*lambda_2
y = (m+1/2)*lambda_2*R/d
for first dark
m = 0
y1dark = lambda_2*R/(2d)
y1bright = = y1dark
lambda_1*R/d = lambda_2*R/(2d)
lambda_2 = 2*lambda_1
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