Question

Two objects of masses

*m*_{1} = 0.40 kg

and

*m*_{2} = 0.92 kg

are placed on a horizontal frictionless surface and a compressed spring of force constant

* k* = 290 N/m

is placed between them as in figure (a). Neglect the mass of the spring. The spring is not attached to either object and is compressed a distance of 9.6 cm. If the objects are released from rest, find the final velocity of each object as shown in figure (b). (Let the positive direction be to the right. Indicate the direction with the sign of your answer.)

Answer #1

**let v1 and v2 are the speeds of m1 and m2 after they
move they from each other.**

**Apply conservation of momentum**

**m1*v1 = m2*v2**

**0.04*v1 = 0.92*v2 ----(1)**

**Apply conservation of energy**

**initial mechanical energy = final mechanical
energy**

**(1/2)*k*x^2 = (1/2)*m1*v1^2 + (1/2)*m2*v2^2**

**(1/2)*290*0.096^2 = (1/2)*0.4*v1^2 + (1/2)*0.92*v2^2
---(2)**

**on solving the above two equations we get**

**v1 = 2.58 m/s
v2 = 0.112 m/s**

**so, if m1 is towards right**

**the answers are
v1 = 2.58 m/s
v2 = -0.112 m/s**

**if m2 is towards right
the answers are
v1 = -2.58 m/s
v2 = 0.112 m/s**

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