Question

An optical disk drive in your computer can spin a disk at up to 10,000 rpm. If a particular disk is spun at 8410 rpm while it is being read, and then is allowed to come to rest over 0.301 seconds, what is the magnitude of the average angular acceleration of the disk?

If the disk is 12.0 cm in diameter, what is the magnitude of the tangential linear acceleration of a point 1/3 of the way out from the center of the disk?

Answer 1

here,

initial angular speed , wi = 8410 rpm

wi = 8410 * 2pi/60

wi = 880.5 rad/s

let the angular acceleration is a

Using first equation of motion

0 - 880.5 = a * 0.301

a = 2925 rad/s^2

the magnitude of average acceleration is 2925 rad/s^2

magnitude of tangential linear acceleration = a * radius

magnitude of tangential linear acceleration = 2925 * (0.12/2)/3

magnitude of tangential linear acceleration = 58.51 m/s^2

the magnitude of tangential linear acceleration is 58.51 m/s^2