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Multiple Choice Problem 23.10

A light beam has a wavelength of 400 nm in a material of refractive index 2.00.

Part A

In a material of refractive index 2.50, its wavelength will be

ANSWER:

In a material of refractive index 2.50, its wavelength will be: (multiple choice)

a) 800 nm .

b) 400 nm .

c) 200 nm .

d) 320 nm .

e) 160 nm .

Answer 1

Solution -:

given data;

lembda 1 = 400 nm

n1 = 2.00

n2 = 2.50

   frequency   f   =   velocity / wavelength

So,

=> v1 / lembda 1  = v2 / lembda 2

   also   v   =   c / n

Then ,

c   =   speed of light

n =   refractive index of the medium

So,

   => (c/n1) / lembda 1  =   (c/n2)/ lembda 2

So,

lembda1 / lembda 2=   n2 / n1

Put values..

400 nm / lembda 2 =   2.50  / 2.00

Then find lembda 2

So,

lembda 2 = 400*2 / 2.50

lembda 2 = 800 / 2.50

lembda2 = 320 nm (Option d is Answer)

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