Two disks are rotating about the same axis. Disk A has a moment of inertia of 3.7 kg · m2 and an angular velocity of +7.7 rad/s. Disk B is rotating with an angular velocity of -10.4 rad/s. The two disks are then linked together without the aid of any external torques, so that they rotate as a single unit with an angular velocity of -2.5 rad/s. The axis of rotation for this unit is the same as that for the separate disks. What is the moment of inertia of disk B?
Angular momentum = I?
I1 = Moment of inertia of disk A = 3.7 kg.m^2
?1= angular velocity of disk A = 7.7 rad/s
Angular momentum of disk A = (3.7)(7.7)=28.49
I2= momentof inertia of disk B
?2 = angular velocity of disk B=(-10.4) rad/second\
?= angular velocity of disk A and disk B combined= -2.5rad/s
Using the consrvation of angular momentum
I1?1 + I2?2 = ( I1+ I2)?
28.49 -I2(10.4) = (3.7+ I2)(-2.5)
Solve above equation.
I2= 4.78 kg.m^2
Moment of inertia of second B = 4.78 kg m2
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