Question

If 3.37 m3 of a gas initially at STP is placed under a pressure of 2.30 atm , the temperature of the gas rises to 33.0 ?C. What is the volume?

Answer #1

Using PV = nRT

The gas is going to retain the same number of molecules, and the
constant R remains the same, so:

=

n and R cancel out for the previously explain reason; so you
have P_{1}V_{1}/T_{1} =
P_{2}V_{2}/T_{2}

STP is defined as 273K (0 C) and 100kPa (or 10^5 Pa)

1 atm = 1.013 x 10^5 Pa

No conversion necessary for m^3

Substituting: (100,000)(3.37)/ 273 = (2.30 x
101,300)(V_{2}) / (273 + 33)

(V_{2}) = 1234.43 / 761.40

(V_{2}) = 1.621 m^{3}

Thankyou !!! Have fun

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