Question

A diverging lens with a focal length of -13 cm is placed 12 cm to the right of a converging lens with a focal length of 19 cm . An object is placed 31 cm to the left of the converging lens.

**A.Where will the image be if the diverging lens is 39 cm
from the converging lens?**

Express your answer using two significant figures. di = ? cm from the diverging lens

Answer #1

here,

for the first lens ,

the object distance , d01 = 31 cm

focal length , f1 = - 13 cm

let the image distance be di1

using the lens formula

1/f1 = 1/di1 + 1/do1

- 1/13 = 1/di1 + 1/31

di1 = - 9.16 cm

for the seccond lens

the object distance , d02 = 39 - (-di1) = 48.16 cm

focal length , f2 = 19 cm

let the image distance be di2

using the lens formula

1/f2 = 1/di2 + 1/do2

1/19 = 1/di1 + 1/48.16

di2 = 31.4 cm

the final image distance is 31.4 cm

the distance from diverging lens = 31.4 + 31 cm = 62.4 cm

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