Question

A converging lens (f = 14.2 cm) is located 23.2 cm to the left of a diverging lens (f = -4.59 cm). A postage stamp is placed 37.1 cm to the left of the converging lens. (a) Locate the final image of the stamp relative to the diverging lens. (b) Find the overall magnification.

Answer #1

We have lens formula as

For converging lense f = 14.2 and u = -37.1 cm

magnification

Now object distance for the diverging lens is 23.2 -23.0 = 0.2 cm

**so image will form at a distance of 0.19 cm left to the
diverging lens.**

**So total magnification will be**

A converging lens (f = 11.3 cm) is located 24.0 cm to
the left of a diverging lens (f = -5.42 cm). A postage
stamp is placed 46.0 cm to the left of the converging lens.
(a) Locate the final image of the stamp relative
to the diverging lens. (b) Find the overall
magnification.

A converging lens (f = 11.0 cm) is located 23.6 cm to the left
of a diverging lens (f = -4.51 cm). A postage stamp is placed 52.7
cm to the left of the converging lens. (a) Locate the final image
of the stamp relative to the diverging lens. (b) Find the overall
magnification.

A converging lens (f1 = 12.7 cm) is located 30.6 cm
to the left of a diverging lens (f2 = -6.48 cm). A
postage stamp is placed 33.9 cm to the left of the converging lens.
Locate the final image of the stamp relative to the diverging
lens.

A converging lens (f1 = 11.9 cm) is located 27.6 cm
to the left of a diverging lens (f2 = -5.94 cm). A
postage stamp is placed 34.8 cm to the left of the converging lens.
Find the overall magnification.

A converging lens with focal length 10.0 cm is
located 28.0 cm to the left of a diverging lens
with focal length - 8.0 cm. An object is placed 36
cm to the left of the converging lens. Where is the final image
located relative to the diverging lens?
Select one:
a) at infinity
b) 13.9 cm to the right
c) 14.2 cm to the right
d) 5 cm to the left

A converging lens (f1 = 22.0 cm) is located 43.0 cm
to the left of a diverging lens (f2 = -26.0 cm). An
object is placed 38.0 cm to the left of the converging lens.
Relative to the diverging lens, where is the final image
located?
Is it real or virtual?
How does the size of the image compare to the size of the
object?

A converging lens is placed at
x = 0,
a distance d = 11.0 cm to the left of a diverging lens
as in the figure below (where FC and
FD locate the focal points for the converging
and the diverging lens, respectively). An object is located at
x =
−1.10
cm to the left of the converging lens and the focal lengths of
the converging and diverging lenses are
3.50 cm
and
−8.60 cm,
respectively.
HINT
(a)
Determine the...

A converging lens is placed at
x = 0,
a distance d = 11.0 cm to the left of a diverging lens
as in the figure below (where FC and
FD locate the focal points for the converging
and the diverging lens, respectively). An object is located at
x =
−1.10
cm to the left of the converging lens and the focal lengths of
the converging and diverging lenses are
3.50 cm
and
−8.60 cm,
respectively.
HINT
(a)
Determine the...

A converging lens (f1 = 24.0 cm) is located
56.0 cm to the left of a diverging lens (f2 =
−28.0 cm). An object is placed to the left of the converging lens,
and the final image produced by the two-lens combination lies 22.1
cm to the left of the diverging lens. How far is the object from
the converging lens?

A converging lens (f1 = 24.0 cm) is located 56.0 cm to the left
of a diverging lens (f2 = -28.0 cm). An object is placed to the
left of the converging lens, and the final image produced by the
two-lens combination lies 21.1 cm to the left of the diverging
lens. How far is the object from the converging lens?

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