In a student experiment, a constant-volume gas thermometer is calibrated in dry ice (?78.5°C) and in boiling pentane (36.1°C). The separate pressures are 0.902 atm and 1.442 atm. Hint: Use the linear relationship P = A + BT, where A and B are constants.
(a) What value of absolute zero does the calibration
yield?
°C
(b) What pressure would be found at the freezing point of
water?
atm
(c) What pressure would be found at the boiling point of
water?
atm
0.902 atm = A + B(-78.5 + 273K) = A + B*194.5K
1.442 atm = A + B(36.1 + 273K) = A + B*309.1K
Solving for simultaneous equations yields
A = -0.0144937 atm
B = 0.00471205 atm/°K
Therefore
P = -0.0144937 atm + (0.00471205 atm/K)*T
(a) At absolute zero, there is zero pressure (P = 0), therefore T = (0. 0144937 atm)/( 0.00471205 atm/K) = 3.08K or -270C
(b) P = -0.0144937 atm + (0.00471205 atm/K)*(0 + 273°K) = 1.272 atm
(c) P =-0.0144937 atm + (0.00471205 atm/K)*(100 + 273°K) = 1.743 atm
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