Question

A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of...

A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of the wheel is 1.55 rad/s at ti = 0.

(a) Through what angle does the wheel rotate between t = 0 and t = 2.00 s? Give your answer in radians and revolutions.
___________rad
___________ rev

(b) What is the angular speed of the wheel at t = 2.00 s?
__________rad/s

(c) What angular displacement (in revolutions) results while the angular speed found in part (b) doubles?
rev

(Use the worked example above to help you solve this problem.)

(a) Find the angle through which the wheel rotates between t = 2.00 s and t = 3.70 s.

___________ rad

(b) Find the angular speed when t = 3.70 s.
_____________rad/s

(c) What is the magnitude of the angular speed five revolutions following t = 3.70 s?
____________rad/s

Homework Answers

Answer #1

For later parts, in the similar manner, please find angular displacement taking time = 3.70 s (as in part a)

Then subtract the obtained value from angular displacement obtained for 2.00 s

for (b) again, use exact same equation, just put t = 3.70 s

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