Question

# A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of...

A wheel rotates with a constant angular acceleration of 3.90 rad/s2. Assume the angular speed of the wheel is 1.55 rad/s at ti = 0.

(a) Through what angle does the wheel rotate between t = 0 and t = 2.00 s? Give your answer in radians and revolutions.
___________ rev

(b) What is the angular speed of the wheel at t = 2.00 s?

(c) What angular displacement (in revolutions) results while the angular speed found in part (b) doubles?
rev

(a) Find the angle through which the wheel rotates between t = 2.00 s and t = 3.70 s.

(b) Find the angular speed when t = 3.70 s.

(c) What is the magnitude of the angular speed five revolutions following t = 3.70 s?

For later parts, in the similar manner, please find angular displacement taking time = 3.70 s (as in part a)

Then subtract the obtained value from angular displacement obtained for 2.00 s

for (b) again, use exact same equation, just put t = 3.70 s

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