If Young's double slit experiment were submerged in water (n=1.33), how would the inteference pattern change?
On immersing the apparatus in water, the speed of wave travelling in water decreases and hence it’s wavelength decreases as v ? ?
Thus the new wavelength is 1/n times the the original wavelength since n=?1/?2
The fringe width originally is given by ?1=?D/2d
The new fringe width within water will be given by ?2=?D/2nd or ?2=?1/n
Thus the fringe width decreases by a factor of n when immersed in water.
For water, n = 1.33
So:
?2=?1/1.33
That is, the fringe width decreases by a factor of 1.33 when immersed in water.
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