Two children, each with a mass of 24.6 kg, are at fixed locations on a merry-go-round (a disk that spins about an axis perpendicular to the disk and through its center). One child is 0.78 m from the center of the merry-go-round, and the other is near the outer edge, 2.79 m from the center. With the merry-go-round rotating at a constant angular speed, the child near the edge is moving with translational speed of 11.0 m/s.
(a) What is the angular speed of each child?
? 0.78 m | = _____ rad/s | |
? 2.79 m | = _____ rad/s |
(b) Through what angular distance does each child move in 5.0
s?
? 0.78 m | = _____ rad | |
? 2.79 m | = _____ rad |
(c) Through what distance in meters does each child move in 5.0
s?
d 0.78 m | = _____ m | |
d 2.79 m | = _____ m |
(d) What is the centripetal force experienced by each child as he
or she holds on?
Fc, 0.78 m | = _____ N | |
Fc, 2.79 m | = _____ N |
Which child has a more difficult time holding on?
Inner Child or Outer Child
(a)since no external torque is working so angular momentum will be conserved and system will keep moving with same angular velocity.
for child standing at the edge
v=11 m/s(translational velocity)
r=2.79m
since w is not changing so
=3.94 rad/sec
this will be same for both the childs.
(B)
(c)distance moved by child standing at radius 0.78m
=15.366m
distance moved by second child standing at radius 2.79m
s=58.509m
(d)centripital force
child at 0.78m
F=297.87N
for child at 2.79m
F=1065.45N
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