Question

A puck with a mass of 1.2 kg moves with a velocity of 5 m/s in...

A puck with a mass of 1.2 kg moves with a velocity of 5 m/s in the x-direction. It collides with a 1.6 kg puck which is initally stationary. After the collision, the second puck moves at a velocity of 1.44 m/s at an angle of 33 degrees below the x axis.

A) What is the angle of the first puck after the collision?

B)What is the velocity of the first puck after the collision?

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Answer #1

The velocity of the second puck in the x direction is: 1.44*cos 33 = 1.2077 m/s

The velocity of the second puck in the y direction is: -1.44*sin 33 = -0.7843 m/s

Applying the Conservation of Linear Momentum principle to the 2 puck system in the x direction :

Applying the Conservation of Linear Momentum principle to the 2 puck system in the y direction :

The angle made by the first puck is:

A) The angle made by first puck after collision is:

B) Velocity of the first puck after collision is:

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