Question

A 400 turn solenoid with a length of 20 cm and a radius of 3.0 cm carries a current of 3.0 A. A second coil of four turns is wrapped tightly about this solenoid so that it can be considered to have the same radius as the solenoid. Find the following when the current in the solenoid increases to 5.0 A in a period of 0.90 s.

(a) the change in the magnetic flux through the coil

_______T·m²
(b) the magnitude of the average induced emf in the coil
______ V

Answer 1

A. B= NIo / L

B = ( 400 * 3A * 4 *10^-7) /?. 20

B = 7.53 * 10^-3 T

= B * A

= 7.53 * 10^-3 * 3.14 *. 030 * 0.03

= 2.13 * 10^-6 T-m²

B. V = - N * Del / del t

Del = A * Del B

Bfinal = 400 * 5A * 4 * 3.14 * 10^-7 /. 20

Bfinal = 12. 5 × 10^-3 T-m²

V = - 400 * 3.14 *. 03 *. 03 * (12.5 - 7.53) * 10^-3 /. 90

V = - 6.5 * 10^-5v