Question

A. See the procedures below and answer the questions that follows:

1. Describe a situation where the block moves as the force is applied to it, yet the force does no work over a non-zero time interval. How can this be?

2. Set the initial position of the block to zero, and set the initial velocity to —3 m/s. Run the simulation. When is the work negative? When is it positive? Why?

3. Since the force is constant, what can you say about the acceleration of the block?

4. How can you maximize the final velocity of the block? Can you do the same amount of work and have the block moving more slowly?

5. Create a graph to represent the force (y-axis) and the position (x-axis).

6. What is the area under the curve of this graph?

Answer 1

1.

If Force is perpendicular to the displacement then the workdone is ZERO for the non zero time.

2.

If the force is in the direction of the displacement then the work done is positive, if the force is in the direction opposite to the displacement then the workdone is negative. and if force is perpendicular to the displacement the work is zero

By equation,

3.

Acceleration of the block also constant by equation,

4)

Workdone is same as long as the force and displacement is same, so yes we can slower the velocity for the same amount of work

5)

Draw graph by considering the force on y axis and displacement on x axis

6)

The area under the graph represent the workdone