Question

For the polarizers in the figure below, suppose the incident light is linearly polarized, the transmitted intensity (through both polarizers) is 0.19 ? I0, and the axis of second polarizer makes an angle ? = 54° with the axis of the first polarizer. What is the angle the initial direction of polarization makes with the first polarizer?

Answer #1

**let Io is the intensity of linearly polarized
light.**

**given**

**theta2 = 54 degrees**

**theta1 = ?**

**Intensity through first polarizer,**

**I1 = Io*cos^2(theta1)**

**Intensity through second polarizer,**

**I2 = I1*cos^2(theta2)**

**0.19*Io = Io*cos^2(theta1)*cos^2(theta2)**

**0.19 = cos^2(theta1)*cos^2(theta2)**

**cos^2(theta1) = 0.19/cos^2(theta2)**

**cos^2(theta1) = 0.19/cos^2(54)**

**cos^2(theta1) = 0.5499**

**cos(theta1) = sqrt(0.5499)**

**cos(theta1) = 0.7416**

**theta1 = cos^-1(0.7416)**

**= 42.1 degrees
<<<<<<<<<---------------------Answer**

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