Question

Two particles, with identical positive charges and a separation of 2.77 × 10-2 m, are released from rest. Immediately after the release, particle 1 has an acceleration a1 whose magnitude is 4.70 × 103 m/s2, while particle 2 has an acceleration a2 whose magnitude is 10.1 × 103 m/s2. Particle 1 has a mass of 6.73 × 10-6 kg. Find (a) the charge on each particle and (b) the mass of particle 2.

Answer 1

Step One
=======
Find the force on particle one.

F = m*a
m = 6.73 * 10^-6 kg
a = 4.7 * 10^3 m/s^2
F = 0.031631N

Step Two
======
Find the charge on each particle.

F = kq1*q2/r^2
F = 0.031631 N
k = 9.11*10^11 N*m^2/c^2
q1 = q2 = x
r = 2.90 * 10^-2 m

0.0253 N = 9.11*10^11 x^2/ (2.90*10^-2)^2
0.0253 N * (2.90 * 10^-2)^2 / 9.11* 10^11 = x^2
2.34 * 10^ - 17 = x^2
x = 4.83 * 10^-9 c.

Step Three
========
Find Mass One.
F = 0.031631 N
a = 10.1 * 10^3
m = F/a = 0.031631/10.1 * 10^3
m = 2.98 * 10^-6 kg

varify calculation by yourself procedureis correct