Question

Light of intensity I0 is polarized vertically and is incident on an analyzer rotated at an...

Light of intensity I0 is polarized vertically and is incident on an analyzer rotated at an angle ? from the vertical. Find the angle ? if the transmitted light has intensity I = (0.750)I0, I = (0.500)I0, I = (0.250)I0, and I = 0. (Enter your answers in degrees.)

(a) I = (0.750)I0 °

(b) I = (0.500)I0 °

(c) I = (0.250)I0 °

(d) I = 0 °

Homework Answers

Answer #1

theta = A

when polarized light passes thorugh polarizer, Intensity will be according to Malus's law:

I = I0*(cos A)^2

Cos A = sqrt (I/I0)

A = arccos sqrt (I/I0)

Part (a),

when given that, I = 0.750*I0

I/I0 = 0.750

So, Angle will be

A = arccos (sqrt 0.750) = 30 deg

Part (b),

when given that, I = 0.500*I0

I/I0 = 0.500

So, Angle will be

A = arccos (sqrt 0.500) = 45 deg

Part (c)

when given that, I = 0.250*I0

I/I0 = 0.250

So, Angle will be

A = arccos (sqrt 0.250) = 60 deg

Part (d),

when given that, I = 0*I0

I/I0 = 0

So, Angle will be

A = arccos (sqrt 0) = 90 deg

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