Question

# Two seconds after being projected from ground level, a projectile is displaced 40 m horizontally and...

Two seconds after being projected from ground level, a projectile is displaced 40 m horizontally and 53 m vertically above its launch point. Its horizontal component of initial velocity is v0x=20 m/s. Its vertical component of initial velocity is v0y=36 m/s. At the instant the projectile reaches maximum height above ground level, the displacement is x=74 m.

Answer questions a, b, and c below. Show all work and details. Give explanation for your answer.

a) What is the horizontal range of the projectile?

b) What would be the velocity of the projectile when is at the half of the maximum height?

c) By adjusting the launching angle with the same launching speed, the projectile hits a target at 165 m away horizontally from the launching point, but at the same height. Find the maximum height that this projectile reaches.

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