An ac generator supplies a peak (not rms) voltage of 208 V at 60.0 Hz. The generator is connected in series with a 200-mH inductor, a 45-?F capacitor and a 100-? resistor. Determine the rms current in the circuit.
(a) 1.5 A, V leads I
(b) 1.1 A, I leads V
(c) 1.5 A, I leads V
(d) 2.11 A, V leads I
* I don't understand the whole V lead, I lead part or how to know it goes from one specific lead to another. Please explain if possible.
PART 2:
At what frequency would the current in the circuit in Problem 10 become maximum?
(a) 60.0 Hz
(b) 53.0 Hz
(c) 85.7 Hz
(d) 98.9 Hz
(c) 1.5 A, I leads V
explanation
We know that
Irms = Vrms/Z
Vrms = V/1.414 = 208/1.414 = 147 V
Z = sqrt (R^2 + (Xl - Xc)^2)
Z = sqrt[100^2 + (2 x 3.14 x 60 x 200 x 10^-3 - 1/(2 x 3.14 x 60 x 45 x 10^-6))^2] = 101.33
Irms = 147/101.33 = 1.5 A
(c) 1.5 A, I leads V
The current leads voltage in RLC circuit. And phase should be less than 90.
2)For max current
Z = R
this happens when, Xl = Xc
2 pi f L = 1/2 pi f C
f = 1/2 pi sqrt (LC) = 1/2 x 3.14 sqrt (200 x 10^-3 x 45 x 10^-6) = 53.1 Hz
Hence, f = 53.1 Hz
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