Current in the wire, I = 3.0 A
Distance of a point from the wire, r = 50 m
Magnitude of the magnetic field at this point is given as:
B
Where,
= Permeability of free space =
= 4* 3.14*10^-7*2*3/ (4*3.14*50)
= 1.2*10^-8T
Hence, the magnitude of the magnetic field at a point 20 cm from the wire is 1.2*10^-8 T.......ANS
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