Imagine we have a force per unit mass of f(x,v) = q(x)p(v). How would you go about solving for the connection between the v and the x of an object moving under this force law? If the object starts at rest at x=0, what will be its v(x) if the the force law is f(x,v) = Ax {nevermind the time}
Given in the question force is the function of x and v
Where x is a distance and v velocity.
Now by using equation v2 = u2 + 2as where u =0 and as mass is unit given .v2 = 2a×1×s
Now a×1 can be considered as force hence replacing from intial eqation.
v2 = 2×q(x)×p(v)×x this is the relation between x and v.
Now x=0 and we know force= m×a
And a= (v-u)/t
Replacing as mass is unit and u=0
Ax=v/t
Hence v= Axt
Thanks
Please give your valuable feedback and sorry for the mistake
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