Question

Consider a steel guitar string of initial length 9m and
cross-sectional area 2.3mm^{2}. The Young's modulus of the
steel is *Y*=2.00×10^{11}Pa. How far would such a
string stretch under a tension of 1650N?

?*L*=

I can't seem to get this problem even with other examples. Please solve and show all steps and if possible explanation. Thanks!

Answer #1

Young's modulus of the steel,

Initial Length,

Area of string,

Tension ,

From Hooke's Law,

Therefore,

The string would stretch for a length of 0.0323 m.

A steel wire has the following properties: Length = 5.00 m
Cross-sectional area = 4.60×10−2 cm2 Young's modulus = 2.0×1011Pa
Shear modulus = 0.84×1011Pa Proportional limit = 3.60×108Pa
Breaking stress = 11.0×108Pa The proportional limit is the maximum
stress for which the wire still obeys Hooke's law (point B in
(Figure 1)). The wire is fastened at its upper end and hangs
vertically.
A) How great a weight can be hung from the wire without
exceeding the proportional limit?
B)...

Find the axial displacement of a rod given properties
L(length), A (cross sectional area), E (Modulus) impacted axially
by a mass m moving with a velocity v0?

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