A mountain climber of mass m hangs onto a rope to keep from sliding down a smooth, ice covered slope. Find the formula for the tension in the rope when the slope is inclined at an angle θ above the horizontal. Check your results in the limits θ=0 and θ=90degrees.
Solution :
Here, The forces along the plane acting on the man of mass m are :
And, The net force acting onthe man is : mg sin θ - T (down the plane).
If this is zero he may climb down with unifor velocity, a = 0.
If a > 0, then
Net force, mg sinθ - T = ma
T = mg sinθ - ma = m ( g sinθ - a)
.
For θ = 90 : vertically down.
Since : sin(90) = 1
T = m (g - a) = m g (if a = 0)
For θ = 0 :
mg sin(0) = 0 (no force acting).
No downward motion.
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