Question

The allowed energies of a simple atom are 0.00 eV, 3.73 eV , and 5.58 eV .

**Part A**

What wavelengths appear in the atom's emission spectrum?

Enter your answers in ascending order separated by commas.

**Part B**

What wavelengths appear in the atom's absorption spectrum?

Enter your answers in ascending order separated by commas.

Answer #1

Part B:

Absorption will take place when electron moves from

1) 0 eV to 3.73 eV

2) 0 eV to 5.58 eV

3) 3.73 eV to 5.58 eV

So wavelength corresponding to the absorption for 0 eV to 3.73 eV = 3330 Å

Wavelength corresponding to the absorption for 0 eV to 5.58 eV = 2226 Å

Wavelength corresponding to the absorption for 3.73 eV to 5.58 eV = 6715 Å

So ascending order = 2226 Å, 3330 Å, 6715 Å

The allowed energies of a simple atom are 0.00 eV, 4.21 eV , and
5.63 eV .
Part A
What wavelengths appear in the atom's emission spectrum?
Enter your answers in ascending order separated by commas.
Part B
What wavelengths appear in the atom's absorption spectrum?
Enter your answers in ascending order separated by commas.

The allowed energies
of a simple atom are 0.00 eV, 4.05 eV , and 5.12 eV .
Part
A
What wavelengths
appear in the atom's emission spectrum?
Enter your answers in
ascending order separated by commas.
Part
B
What wavelengths
appear in the atom's absorption spectrum?
Enter your answers in
ascending order separated by comma

The allowed energies of a quantum system are 0.0 eV, 6.0 eV ,
and 8.5 eV . What wavelengths appear in the system's emission
spectrum? Enter your answers in ascending order separated by
commas.

The allowed energies of a simple atom are 0.0 eV, 5.0 eV, and
8.0 eV. An electron traveling at a speed of 1.9 x 10^6 m/s
collisionally excites the atom. A) What is the minimum speed the
electron could have after the collision? B) What is the maximum
speed the electron could have after the collision?

a) An electron in a quantum system has allowed energies 1eV,
3eV and 9 eV. What wavelengths are observed in the emission
spectrum of this system? Show your work.
b) If you must choose from wavelengths obtained in part a) as
light source for a photoelectric effect demonstration, with which
material(s) will you build your cathode, and with what wavelength
you would shine on it?
Show your work.

Exercise2
The absorption spectrum of an atom consists of the wavelengths
200nm, 300 nm, and 500nm.
a) Draw the atom's energy level diagram. Label each level with
the energy and the principal quantum number.
b) What wavelengths are seen in the atom's emission
spectrum?

Two point charges, Q1 = 3.6 μC and Q2 =
-1.3 μC , are placed on the x-axis. Suppose that Q2 is
placed at the origin, and Q1 is placed at the coordinate
x1 = −6.0 cm (Figure
1).
Part A) At what point(s) along the xx axis is the electric field
zero? Determine the x-coordinate(s) of the point(s). Express your
answer using two significant figures. If there is more than one
answer, enter your answers in ascending order separated...

Two point charges, Q1 = 2.9 μC and Q2
= -1.3 μC , are placed on the x axis. Suppose
that Q2 is placed at the origin, and Q1 is placed
at the coordinate x1 = − 4.0 cm (Figure 1).
Part A
Part complete
At what point(s) along the x axis is the electric field
zero? Determine the x-coordinate(s) of the point(s).
Express your answer using two significant figures. If there is
more than one answer, enter your answers...

One series of lines in the hydrogen spectrum is caused by
emission of energy accompanying the fall of an electron from outer
shells to the fourth shell. The lines can be calculated using the
Balmer-Rydberg equation:
1λ=R∞[1m2−1n2]
where m=4, R∞ = 1.097×10−2nm−1, and nis an
integer greater than 4.
Part A
Calculate the wavelengths in nanometers of the first two lines
in the series.
Express your answers using four significant figures separated by
a comma.
Part B
Calculate the energies...

1) The Pauli Exclusion Principle tells us that
no two electrons in an atom can have the same four quantum
numbers.
Enter ONE possible value for each quantum number of an electron
in the orbital given.
Orbital
n
l
ml
ms
1s
There are a total of values possible for
ml.
2s
There are a total of values possible for
ml.
2) The Pauli Exclusion Principle tells us that
no two electrons in an atom can have the same four...

ADVERTISEMENT

Get Answers For Free

Most questions answered within 1 hours.

ADVERTISEMENT

asked 15 minutes ago

asked 38 minutes ago

asked 51 minutes ago

asked 58 minutes ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 1 hour ago

asked 2 hours ago

asked 2 hours ago

asked 2 hours ago