Question

In a performance test, each of two cars takes 9.5 s to accelerate from rest to 28 m/s. Car A has a mass of 1434 kg, and car B has a mass of 1868 kg. Find the net average force that acts on (a) car A and (b) car B during the test.

Answer 1

Average acceleration of both cars, a = change in velocity/time
                                         = (28-0)/9.5
                                                       = 2.95 m/sec²

Average force = mass* acceleration
a) net average force on car A = 1434*2.95 = 4226.5 N

b) net average force on Car B = 1868*2.95 = 5505.7 N