(HW09-28.7) A negative charge q = ?3.40×10?6 C is located at the origin and has velocity ?? =(7.50×104m/s)?^+((?4.90)×104m/s)j^.
A) At this instant what is the magnetic field produced by this charge at the point x = 0.250 m , y = -0.250 m , z = 0?
Enter the x, y, and z components of the magnetic field separated by commas.
Bx, By, Bz =
Given
= velocity of charge = 75000 i - 49000 j
= (0.250 - 0 ) i + (- 0.250 - 0 ) j + (0 - 0 ) k = 0.250 i - 0.250 j + 0 k
|r| = sqrt (0.2502 + (- 0.250)2) = 0.353 m
magnetic field is given as
= (/4) (q) ( x ) /r3
= (10-7) (- 3.4 x 10-6) ((75000 i - 49000 j ) x (0.250 i - 0.250 j + 0 k))/(0.353)3
= (10-7) (- 3.4 x 10-6) (- 6500 k) /(0.353)3
= 0 i + 0 j + (5.024 x 10-8) k
= 0 i + 0 j + 0.05024 uT k
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