Question

A long thin rod of mass M and length L is situated along the y axis...

A long thin rod of mass M and length L is situated along the y axis with one end at the origin. A small spherical mass m1 is placed at the location P, which is at a distance d from the origin.

If L = 2.00 ? 104 m, d = 18.0 ? 104 m,M = 14.0 ? 106 kg,and m1 = 8.00 ? 106 kg,what is the value of this potential energy?

Homework Answers

Answer #1

Gravitational potential energy between two body is given by

Since the mass are distributed so we have to use integration method to find the total potential energy

mass per unit length of the rod is

lets take a small mass "dm" at a distance "r' from the point P so

So the value of potential energy is -4.401*10^-2 J or -0.04401 J

Know the answer?
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for?
Ask your own homework help question
Similar Questions
A thin, non conducting rod with length L lies along the positive X-Axis with one end...
A thin, non conducting rod with length L lies along the positive X-Axis with one end at the origin. The rod carries a charge distributed along its length of λ(x) = bx/L. Determine the electric potential along the X-Axis at the point x = 2 cm if L = 1 cm and b = 50 pC/m. Answer = (0.17 V)
A thin, 1-dimensional, uniform rod of mass M and length L lies on the x axis...
A thin, 1-dimensional, uniform rod of mass M and length L lies on the x axis with one end at the origin. (a) Find its moment of inertia tensor about the origin. (b) Find the moment of inertia tensor if the rod’s center is located at the origin.
6) A rod with length "l" is lied along x-axis. The charge density of the rod...
6) A rod with length "l" is lied along x-axis. The charge density of the rod is "a". Calculate the potential of the rod for a the point p on x-axis. 7) A rod with length "l" is lied along x-axis. The charge density of the rod is "a". Calculate the Electric field of the rod for a point p on x-axis.
A thin rod of length l and uniform charge per unit length λ lies along the...
A thin rod of length l and uniform charge per unit length λ lies along the x axis as shown figure. (a) Show that the electric field at point P, a distance y from the rod, along the perpendicular bisector has no x component and is given by E=(2kλsinθ0)/y. (b) Using your result to (a), show that the field of a rod of infinite length is given by E=2kλ/y.
A uniform rod of length L and mass M is free to swing about an axis...
A uniform rod of length L and mass M is free to swing about an axis that is perpendicular to the rod. The axis is a distance x from the rod's center of mass. a) Find the period of oscillations for small angles as a function of L and x with appropriate constants. b) make a sketch of the period as a function of x. If you use a spread sheet you may assume that L=1.0 m, then your graph...
A thin rod of length L has uniform linear mass density λ (mass/length). (a) Find the...
A thin rod of length L has uniform linear mass density λ (mass/length). (a) Find the gravitational potential Φ(r) in the plane that perpendicularly bisects the rod where r is the perpendicular distance from the rod center. Assume the gravitational potential at infinity is zero. (b) Find an approximate form of your expression from part (a) when r >> L. (c) Find an approximate form of your expression from part (a) when r<< L.
A thin rod sits along the xx axis with one end at x= -1.4 m and...
A thin rod sits along the xx axis with one end at x= -1.4 m and the other end at x= 3.5 m. The rod has a non-uniform density that increases linearly from 1.1 kg/m at the left end to 3.0 kg/m at the right end a What is the total mass of the rod? answer 10 kg b Where is the center of mass of the rod located? find it
Consider a thin rod of length L=2.58m and mass m1=1.27 kg, and a hollow (empty) sphere...
Consider a thin rod of length L=2.58m and mass m1=1.27 kg, and a hollow (empty) sphere of radius R=0.16 m and mass of m2=0.82 kg. Sphere is at one end of the rod and the other end of the rod is fixed and oscillate like a pendulum (simple harmonic oscillations, SHM) with small-angle oscillations. When ? ?? ?????, ???? ≈ ?. a) Derive a second order differential equation for this pendulum to confirm the oscillation is SHM.(b) Compare the above...
A thin, rigid, uniform rod has a mass of 1.40 kg and a length of 2.50...
A thin, rigid, uniform rod has a mass of 1.40 kg and a length of 2.50 m. (a) Find the moment of inertia of the rod relative to an axis that is perpendicular to the rod at one end. (b) Suppose all the mass of the rod were located at a single point. Determine the perpendicular distance of this point from the axis in part (a), such that this point particle has the same moment of inertia as the rod...
The uniform thin rod in the figure below has mass M = 2.00 kg and length...
The uniform thin rod in the figure below has mass M = 2.00 kg and length L = 2.87 m and is free to rotate on a frictionless pin. At the instant the rod is released from rest in the horizontal position, find the magnitude of the rod's angular acceleration, the tangential acceleration of the rod's center of mass, and the tangential acceleration of the rod's free end. HINT An illustration shows the horizontal initial position and vertical final position...
ADVERTISEMENT
Need Online Homework Help?

Get Answers For Free
Most questions answered within 1 hours.

Ask a Question
ADVERTISEMENT